Please I need a help in solving this
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Hey Mathematicians,
DPB=BQD
180-DPB=180-BQD
DPA=BQC
In ∆DAP and ∆BCQ
ADP=CBQ
DP=BQ
DPA=BQC
Therefore by ASA criterion, ∆ADP=∆CBQ.
DPB=BQD
180-DPB=180-BQD
DPA=BQC
In ∆DAP and ∆BCQ
ADP=CBQ
DP=BQ
DPA=BQC
Therefore by ASA criterion, ∆ADP=∆CBQ.
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answer of above. hope it helps u
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