Please I need help answering this question. David has a hose that is 27 ft long. He wants to cut it into two pieces so that the longer piece is 3 ft more than 2 times the length of the shorter piece.
How long will each piece of hose be?
Enter your answers in the boxes.
Shorter piece:
ft
Longer piece:
ft
Answers
Answered by
3
- Let the length of shorter piece be x ft.
- so '' '' '' '' '' '' = 2 x + 3
A/Q, x + 2 x + 3 = 27
3 x = 24
x = 8
- Length of shorter piece = x = 8 ft.
- '' '' longer '' = 2 x + 3 = 16 +3 = 19 ft.
Thank u.
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amani2004:
Are you a girl or a boy
Answered by
3
let x and y be the length of the longer and the shorter pieces of the hose respectively.
By question,
x + y = 27 --- (1)
and,
x - 2y = 3 --- (2)
subtracting (1) by (2), we get,
y-(-2y) = 27-3
=> 3y = 24
=> y = 24/3
=> y = 8
putting y = 8 in (1)
x + 8 = 27
=> x = 27-8
=> x = 19
Therefore, the length of the shorter piece is 8 ft and the length of the longer piece is 19 ft
By question,
x + y = 27 --- (1)
and,
x - 2y = 3 --- (2)
subtracting (1) by (2), we get,
y-(-2y) = 27-3
=> 3y = 24
=> y = 24/3
=> y = 8
putting y = 8 in (1)
x + 8 = 27
=> x = 27-8
=> x = 19
Therefore, the length of the shorter piece is 8 ft and the length of the longer piece is 19 ft
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