Question

Please I need help..

Determine the equation of the normal to y = x/x-2 at (0, 0)​

Answer 1

Answer:

We have

y=x

2

⇒

dx

dy

=2x

∴(

dx

dy

)

(0,0)

=0

Thus, the slope of the tangent at (0,0) is 0. Ergo equation of the tangent is given as,

(y−0)=0(x−0)⇒y=0

The slope of the normal at (0,0) is

Slope of the tangent at(0,0)

−1

=−∞.

Therefore, the equation of the normal at (0,0) is given as,

(y−0)=−∞(x−0)⇒x=0

Step-by-step explanation:

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