Question

PLEASE I NEED IT URGENTLY

a copper wire of resistivity 1.63*10^-8 has cross section area of 10*10^-4cm ^2.calculate thelength of the wire required to make a 20 ohm coil.

Answer 1

Answer:

126.4m

Explanation:

p=1.63*10^-8

A=10.3*10^-4cm^2 = 10.3*10^-8m^2

R=10ohm

L=RA/l

= 20*10.3*10^-8/1.63*10^-8

=206/1.63

=126.4m (approx)

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