Question

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Answer 1

Answer:

1. workdone = force * displacement

displacement =120/40

=3m

2. kinetic energy =1/2*m v^2

=1/2*0.5*8=2J

3.potential energy = mgh

=2*50*9.8

=980J

Answer 2

1 Question:

The work done on an object is 120J when a force of 40N is applied on it. Find the displacement.

Given:

• Work Done on an object is 120 J
• Force applied on it is 40 N

Need To Find:

• The Displacement

Formula Used:

$\nrightarrow\sf{Work\: Done =Force\times Displacement}$

Concept:

Here, we are given the value of work done and force applied on the object. We have to find the displacement. For finding so, just equate all the given values in The Work done Formula..

Solution:

» Work Done= 120 J

» Force applied = 40 N

Equating all the values in Formula..

$\rightarrow\mathsf{Work\: Done=Force\times Displacement}$

$\rightarrow\mathsf{120=40\times Displacement}$

Dividing 120 by 40.

$\rightarrow\mathsf{\large{\frac{120}{40}}=Displacement}$

$\rightarrow\bold{Displacement=3\: m}$

Hence, Displacement of the object is 3 metres.

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2 Question:

Find the kinetic energy of a ball of mass 0.5kg moving with a velocity 8m/s.

Given:

• Mass of the ball is 0.5 kg
• Velocity of the ball is 8 m/s

Need To Find:

• The Kinetic energy of the ball.

Formula Used:

$\nrightarrow\sf{Kinetic\: Energy=\large{\frac{1}{2}}\times m\times {v}^{2}}$

• m is the mass of the body
• v is the velocity with which body is travelling

Concept:

Here, we are given the mass and velocity of the object. We have to find the Kinetic energy of the object. For finding the kinetic energy, Equate all the values in kinetic energy formula.

Solution:

» Mass of the ball, m= 0.5 kg

» Velocity of the ball, v= 8 m/s

Equate all the values in Formula..

$\implies\mathsf{Kinetic\: energy=\large{\frac{1}{2}}\times m\times {v}^{2}}$

$\implies\mathsf{Kinetic\: energy=\large{\frac{1}{2}}\times 0.5\times 8}$

$\implies\mathsf{Kinetic\: energy=0.25\times 8}$

$\implies\bold{Kinetic\: energy=2\: kg{m}^{2}/{s}^{2}}$

Hence, Kinetic energy of the ball is 2kgm²/s²

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3 Question:

Find the potential energy of a stone of a mass 2kg raised to a height of 50m. (Given, g=9.8 m/s²)

Given:

• Mass of stone is 2 kg
• Stone is raised to a height of 50 m
• Gravitation field is 9.8 m/s²

Need To Find:

• The potential energy of the stone

Formula Used:

$\nrightarrow\sf{Potential\: Energy= {m}\times {g}\times {h}}$

• m is mass of the object
• g is the gravitational field of the object
• h is the height of the object

Concept:

Here, we are given mass of the object, height it is raised to and it's gravitational field. We have to find the potential energy of the object. To find the potential energy, equate all the values in Potential energy formula.

Solution:

» Mass of stone, m= 2 kg

» Height stone is raised to= 50 m

» Gravitational field= 9.8 m/s²

Equate all the Values in Formula..

$\dashrightarrow\mathsf{Potential\: Energy= m\times g\times h}$

$\dashrightarrow\mathsf{Potential\: Energy=2\times 9.8\times 50}$

$\dashrightarrow\mathsf{Potential\: Energy=19.6\times 50}$

$\dashrightarrow\bold{Potential\: Energy=980\: kg{m}^{2}/{s}^{2}}$

Hence, the Potential energy of the stone is 980 kgm²/s²

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Required Answers:

$\: \: \: \: \hookrightarrow$ The Displacement of the object is 3 metres.

$\: \: \: \hookrightarrow$ The Kinetic energy of the ball is 2kgm²/s²

$\: \: \: \hookrightarrow$ The Potential energy of the stone is 980 kgm²/s²