Question

please I need proper solution you can see the full diagram in my question list also​

Answer 1

QUESTION:

In the given figure BD and CD are bisectors of angle B and angle C respectively. If angle BAC = 70° and angle ABD = 24° .Then find the measures of angle DCB and angle BCD.

ANSWER:

• $\angle BCD = \angle DCB = 31^{\circ}$

GIVEN:

• BD and CD are bisectors of angle B and angle C respectively.

• Angle BAC = 70°.

• Angle ABD = 24°.

TO FIND:

• Angle DCB

• Angle BCD

EXPLANATION:

Bisector:

Bisector is a line which divides the angle equally on both sides.

$\angle ABD = 24^{ \circ}$

Now let us find the angle DBC

As the bisector divides the two angles equally angle DBC will also equal to 24°.

Now let us find angle ABC

$\angle DBC + \angle ABD =\angle ABC$

$\angle ABC = 24^{ \circ} + 24^{ \circ}$

$\angle ABC = 48^{ \circ}$

Now we can find angle ACB.

Sum of three angles of triangle = 180°

$\angle ABC + \angle BAC + \angle ACB = 180^{\circ}$

$\angle ABC = 48^{\circ}$

$\angle BAC = 70^{\circ}$

$70^{\circ} + 48^{\circ} + \angle ACB = 180^{\circ}$

$118^{\circ} + \angle ACB = 180^{\circ}$

$\angle ACB = 180^{\circ} - 118^{\circ}$

$\angle ACB = 62^{\circ}$

To find angle DCB and angle BCD divide the angle by 2 as bisector divides the angle equally on both sides.

And also DCB and BCD means the same angle inside the smaller triangle.

$Hence \ \angle BCD = \angle DCB = 31^{\circ}$

Answer 2

Answer:

HEY DUDE!!!

SEE THE ATTACHMENT FOR DETAILED SOLUTION TO THE QUESTION ✔️✔️