Question

please i need the answer fast​

Answer 1

Step-by-step explanation:

in the figure.... given information is

AF = AE = x cm

BF = BD = 6cm

CE = CD = 9cm

and r = 3cm

Area of triangle ∆ ABC = ar(∆AOB)+ar(∆BOC)

+ar(∆AOC)

54 cm^2 =[1/2×(x+6)×3] + [1/2×(6+9)×3] +

[1/2×(x+9)×3]

54 cm^2 = 1/2×3 [(x+6)+(6+9)+(x+9)]

54 cm^2 = 1/2×3 (2x+30)

54 cm^2 = 3(x+15)

54 cm^2 = 3x +45

3x = 54 - 45

x = 9/3

x = 3

a/q

the length of side AB = (x+6) = 3+6 = 9cm

the length of side AC = (x+9) = 3+9 = 12cm

hope it helps you