Question

Please I need the answer please any one help me

Answer 1

log ( m + n ) = log m + log n

log m × log m = log m + log n

log n = { log m + log n } ÷ { log m }

log n = { log ( m × n ) } ÷ { log m }

log n = { log mn } ÷ { log m }

log n = log{ mn - m }


Removing log from both sides,


n = mn - m

n = m( n - 1 )

$\dfrac{n}{n - 1 } = m$




Hence, proved.

Answer 2

log ( m + n ) = log m + log n

log m × log m = log m + log n

log n = { log m + log n } ÷ { log m }

log n = { log ( m × n ) } ÷ { log m }

log n = { log mn } ÷ { log m }

log n = log{ mn - m }



n = mn - m

n = m( n - 1 )

n/ n-1 = mn−1n​=m 

Hence, proved.