Question

Please! I need this - lots of points
Prove: ((cosecA-secA)/(cosecA+secA))(cotA-tanA)=secAcosecA-2

Answer 1

Step-by-step explanation:

LHS

((1/sinA-1/cosA)/(1/sinA+1/cosA))(cosA/sinA-sinA/cosA)

=((cosA-sinA)/cosA*sinA)/((cosA+sinA)/cosA*sinA)((cos^2A-sin^2A)/sinA*cosA)

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#hope this will help you

Answer 2

Step-by-step explanation:

here,

LHS

((1/sinA-1/cosA)/(1/sinA+1/cosA))(cosA/sinA-sinA/cosA)

=((cosA-sinA)/cosA*sinA)/((cosA+sinA)/cosA*sinA)((cos^2A-sin^2A)/sinA*cosA)

then,

we get ,

RHS=LHS

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hope this helps you

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