Question

please I need urgent solution.....
Answer is 1/2 but how explain...

Answer 1

It can be done by actually taking each value of x and finding the possible outcomes
if x= 1
$1 \times 1 = 1$
$1 \times 4 = 4 \\ 1 \times 9 = 9 \\ 1 \times 16 = 16$
if x= 2
$2 \times 1 = 2 \\ 2 \times 4 = 8 \\ 2 \times 9 = 18 \\ 2 \times 16 = 32$
if x=3
$3 \times 1 = 3 \\ 3 \times 4 = 12 \\ 3 \times 9 = 27 \\ 3 \times 16 = 48$
if x=4
4×1=4
4×4=16
4×9=36
4×16=64
Therefore no of possible outcomes=16
no of favourable outcomes = 7
Therefore probability=7÷16

Answer 2

Given that x is selected from the numbers 1,2,3 and 4.

Given that y is selected from the numbers 1,4,9 and 16.

Therefore possible pairs are:

{1,1},{1,4},{1,9},{1,16},{2,1},{2,4},{2,9},{2,16},{3,1},{3,2},{3,9},{3,16},{4,1},{4,4},{4,9},{4,16}

n(S) = 16.



Let A be the event of getting a product of x and y is less than 16.

n(A) = {1,1},{1,4},{1,9},{2,1},{2,4},{3,1},{3,4},{4,1}.

        = 8.




Therefore the required probability P(A) = n(A)/n(S)

                                                                  = 8/16

                                                                  = 1/2.



Hope this helps!