please I request you to send the clearly for the question asked by me actually I got the answer but some how I did but not understanding so please explain me clearly so,here is you'requestion if two positive integers p and q are written as p=a2b3 and q=a3b;a,bit are prime numbers then verify: lcm(pq)×hcf(pq)=pq
Answers
Answered by
1
P = a^2 * b^3
Q = a^3 * b
L.C.M(P,Q) = a^3 * b^3
H.C.F(P,Q) = a^2 * b
Product of numbers= P*Q = a^2*b^3 *a^3*b = a^5*b^4
L.C.M(P,Q)*H.C.F(P,Q) = a^3*b^3 *a^2*b = a^5*b^4
Hence, verified: product of L.C.M & H.C.F of two numbers = Product of the numbers.
Q = a^3 * b
L.C.M(P,Q) = a^3 * b^3
H.C.F(P,Q) = a^2 * b
Product of numbers= P*Q = a^2*b^3 *a^3*b = a^5*b^4
L.C.M(P,Q)*H.C.F(P,Q) = a^3*b^3 *a^2*b = a^5*b^4
Hence, verified: product of L.C.M & H.C.F of two numbers = Product of the numbers.
Answered by
2
This is the answer of your question
Attachments:
Similar questions
Hindi,
7 months ago
Science,
7 months ago
Chemistry,
1 year ago
CBSE BOARD X,
1 year ago
Hindi,
1 year ago