Question

please I want answer , anyone ? please ​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\sf{y=sin^{-1}\left(x^3\right)}$

$\sf{\implies\,\dfrac{dy}{dx}=\dfrac{1}{\sqrt{1-\left(x^3\right)^2}}\cdot\dfrac{d\left(x^3\right)}{dx}}$

$\sf{\implies\,\dfrac{dy}{dx}=\dfrac{1}{\sqrt{1-x^6}}\cdot3x^2}$

$\sf{\implies\,\dfrac{dy}{dx}=\dfrac{3x^2}{\sqrt{1-x^6}}}$