Math, asked by yasmeenshk980, 2 months ago

please I want answer right now ​

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Answers

Answered by Sagar07Attri05
1

Answer:

using identity

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Answered by MrImpeccable
15

{\Huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}

To Solve:

  1.  (x + y)^2
  2.  (p + 6)^2
  3.  (2a - b)^2
  4.  (5l - 2m)^2
  5.  9r^2 - 4s^2
  6.  (3s + 5t)^2
  7.  (x - 6y)^2
  8.  9m - 16n
  9.  (5a + 7b)^2
  10.  (4x - 6y)2

Solution:

1) (x + y)^2

 :\implies (x + y)^2 \\:\implies (x)^2 + 2(x)(y) + (y)^2 \\\bf{:\implies x^2 + 2xy + y^2}\\\\

2) (p + 6)^2

 :\implies (p + 6)^2 \\:\implies (p)^2 + 2(p)(6) + (6)^2 \\\bf{:\implies p^2 + 12p + 36}\\\\

3) (2a - b)^2

 :\implies (2a - b)^2 \\:\implies (2a)^2 - 2(2a)(b) + (b)^2 \\\bf{:\implies 4a^2 - 4ab + b^2}\\\\

4) (5l - 2m)^2

 :\implies (5l - 2m)^2 \\:\implies (5l)^2 - 2(5l)(2m) + (2m)^2 \\\bf{:\implies 25l^2 - 20ml + 4m^2}\\\\

5) 9r^2 - 4s^2

 :\implies 9r^2 - 4s^2 \\:\implies (3r)^2 - (2s)^2 \\\bf{:\implies (3r - 2s)(3r + 2s)}\\\\

6) (3s + 5t)^2

 :\implies (3s + 5t)^2 \\:\implies (3s)^2 + 2(3s)(5t) + (5t)^2 \\\bf{:\implies 9s^2 + 30st + 25t^2}\\\\

7) (x - 6y)^2

 :\implies (x - 6y)^2 \\:\implies (x)^2 - 2(x)(6y) + (6y)^2 \\\bf{:\implies x^2 - 12xy + 36y^2}\\\\

8) 9m - 16n

 :\implies 9m - 16n \\:\implies (3\sqrt{m})^2 - (4\sqrt{n})^2 \\\bf{:\implies (3\sqrt{m} - 4\sqrt{n})(3\sqrt{m} + 4\sqrt{n})}\\\\

9) (5a + 7b)^2

 :\implies (5a + 7b)^2 \\:\implies (5a)^2 + 2(5a)(7b) + (7b)^2 \\\bf{:\implies 25a^2 + 70ab + 49b^2}\\\\

10) (4x - 6y)2

 :\implies 2(4x) - 2(6y) \\\bf{:\implies 8x - 12y}\\\\

Formula Used:

  •  (a+b)^2 = a^2 + 2ab + b^2
  •  (a-b)^2 = a^2 - 2ab + b^2
  •  a^2 - b^2 = (a+b)(a-b)

Learn More:

\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\bf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\bf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\bf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) - B^{3}\\\\8)\bf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9)\bf\: A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\ \end{minipage}}

Hope it helps!!!

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