Question

please I want the answer of 3,4,5,6​

Answer 1

Answer:

(3) let the number required be x

according to the question we can write as

(4/5)x - 10 = (2/3) x

On rearranging,

(4/5)x - (2/3)x = 10

now taking the LCM of 5 and 3 is 15

(12x - 10x ) / 15 = 10

On cross multiplication,

2x = 150

x = 150 / 2 = 75

so the required number is 75.