Question

please ...I was the solution of it​

Answer 1

Answer:

Step-by-step explanation:

Let AOE = angle1

BOE= angle2

COD = angle 3

AOC = angle 4

BOD = angle 5

1 + 2 = 180 ( linear pair)

So 1 = 90 °

And it is given 1=2=3

So , 3= 90°

→→→ 3+4+5= 180 ( angle on straight line)

90+ 45 + angle5 = 180

5= 45°

Answer 2

Answer:

Angle AOC =45° then angle BOD=45° so AOB is a straight line we know that a straight is= to 180°

then angles AOC+COD+BOD is= to 180° then

45°+45°+x=180° ,x=180-90,x=90° it means angle COD is 90°

So angles AOE=BOE=COD is given then angle AOE and angle BOE is 90°

we have to find angle EOC = AOE+AOC=45°+90°=135°

then angle BOC= BOD+COD= 90°+45°=135° ohk

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