Question

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Find the cost of levelling the ground in form of triangle having the sides 26m,28m and 30m at the rate of Rupee3 per m square.

Answer 1

sides = 26, 28, 30
you have to find the area using heron's formula
$\sqrt{x(x - side1)(x - side2)(x - side3)}$
x stands for semi perimeter
perimeter= 26+28+30=84
semi perimeter= 84/2= 42
area of triangle= √42(42-26)(42-28)(42-30)
= √42×16×14×12
=336 sq m
cost of levelling= ₹3
total cost= 336×3
=₹1008

Answer 2

$\large{\boxed{\bold{Answer:}}}$

The sides of the triangle are 26m,28m and 30m

We will now now find the area Using Heron's Formula:-

$s = \frac{26 + 28 + 30}{2} = \frac{84}{2} = 42m$

a=26, b=28, c=30

$a = \sqrt{42(42 - 26)(42 - 28)(42 - 30)} \\ \\ a = \sqrt{42\times 16 \times 14 \times 12} \\ \\ a = 336 {m}^{2}$

Cost =336×3 = 1008

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