Question

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Find all the zeroes of x^4 + 9x^3 + 28x^2 + 36x + 16, if two of its zeroes are -1 and -2.

Answer 1

Answer:

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Explanation:

x⁴+9x³+28x²+36x +16

given two zeroes of -1 &-2

this can also be written as

(x+1) (x+2)

=> x² + 2x + x + 2

=> x²+ 3x+ 2

now dividing this, we get

division is there in image.

from there we get :

x² +6x+8

now factorising this , we get

x²+4x+2x+8

=> x(x+4)+2(x+4)

=> (x+4)(x+2)

=> x = -4 & -2

therefore other zeroes are -4 & -2 .

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