Question

please integrate this​

Answer 1

Answer:

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Answer 2

Formulas and Quick Tricks for Speed, Time and Distance

1 Kmph = (5/18) m/s

1 m/s = (18/5) Kmph

Speed(S) = Distance(d)/Time(t)

Average Speed = Total distance/Total Time = (d1+d2)/(t1+t2)

When d1 = d2, Average Speed = 2S1S2/(S1+S2), where S1 and S2 are the speeds for covering d1 and d2 respectively.

When t1 = t2, Average Speed = (S1+S2)/2, where S1 and S2 are the speeds during t1 and t2 respectively.

Relative speed when moving in opposite direction is S1+S2

Relative speed when moving in same direction is S1-S2

A person goes certain distance (A to B) at a speed of S1 kmph and returns back (B to A) at a speed of S2 kmph. If he takes T hours in all, the distance between A and B is T(S1S2/(S1+S2)

When two trains of lengths l1 and l2 respectively travelling at the speeds of S1 & S2 respectively cross each other in time t, then the equation is given as S1+S2 = (l1+l2)/t

When a train of length l1 travelling at a speed of S1 overtakes another train of length l2 travelling at speed S2 in time t, then the equation is given as S1-S2 = (l1+l2)/t

When a train of length l1 travelling at a speed of S1 crosses a platform/bridge/tunnel of length l2 in time t, then the equation is given as S1 = (l1+l2)/t

When a train of lengths l travelling at a speed s crosses a pole/pillar/flag post in time t, then the equation is given as s = l/t

If two persons A and B start at the same time from two points P and Q towards each other and after crossing they take T1 and T2 hours in reaching Q and P respectively, then (A’s speed) / (B’s speed) = √T2 / √T1

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