Question

please it is urgent ​

Answer 1

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$\frac{9^x\cdot \:3^5\cdot \:27^3}{3\cdot \:81^4}=27$

$\frac{9^x\cdot \:3^{5-1}\cdot \:27^3}{81^4}=27$

$9^x\cdot \:3^{5-1}\cdot \:27^3\cdot \:81^{-4}=27$

$9^x=\frac{27}{3^{5-1}\cdot \:27^3\cdot \:81^{-4}}$

$9^x = \frac{3^3\cdot3^{16}}{3^4\cdot3^9}$

$9^x = \frac{3^{19}}{3^{13}}$

$9^x = 3^6$

$9^x = 9^3$

$x = 3$

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Answer 2

Step-by-step explanation:

• (9^x×3⁵×27³)/3×81⁴=27
• (3^2x×3⁵×3⁹)/3¹×3¹⁶=3³
• (3^2x+5+9)/3¹+¹⁶=3³

using identity

• n¹/n¹=n¹-¹

• (3)^2x+5+9-17=3³

the bases are same ,their exponent must be equal

• 2x+5+9-17=3
• 2x+14-17=3
• 2x-3=3
• 2x=3+3
• 2x=6
• x=6/2
• x=3