Question

Please it is very urgent I need help...pls solve all the parts of this graph...pls Q.2
I will mark the brainliest whoever answers it the best

Answer 1

Acceleration is slope of V-T graph

So a) 25/3

b) -25/6-3 = -25/3

c) distance is area under V-t graph

So area of ABE = 1/2 3 25 = 75/2 = 37.5

d)average velocity = integration V dt/ dt
limit from 4 to 6

So V = -25/3t + c

put (6,0)
0 = -50+ c
c = 50

So v = -25/3 t + 50

integrate

= -25/3 t^2/2 + 50 t ) / 2

= -25/3 × 18 + 50 × 6 + 25/3 × 8 + 50× 4) /2
= -150+ 300 + 75/8 + 200, /2

= 350 + 75/8 ) /2

= 2800+ 75/ 16

= 2875/16

e) distance covered in BCFE =area of trapezium

= 1/2 ( 25+15) ×3
= 20 × 3 = 60