Question

please it's really very important

Answer 1

let speed of train be x
length of train be y

so y = 18x
Also
(y +330) = 40x

18 x +330 = 40x

22x = 330
x = 330/22 = 15

y = 18x = 18 ×15 = 270

Answer 2

Hi there !
Here's the answer:

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Given,
Length of platform = 330m
Time taken to cross platform = 40 sec
Time taken to cross man standing on platform = 18 sec

Let length of train be x m
=>$Speed = \frac{Distance}{time}$

$Speed\: of\: train = \frac{330+x}{40}$---(1)

$Speed\: of\: train = \frac{x}{18}$ ---(2)

Equate (1) & (2)

=> $\frac{330+x}{40} = \frac{x}{18}$

=> 18(330+x) = 40x
=> 5940+18x = 40x
=> 22x = 5940
=> x = 270

•°• Length of train = 270m

Now,
$Speed\: of\: train = \frac{x}{18}$
= $\frac{270}{18}$
= 15

•°• Speed of train = 15 mps

$15 mps = 15 × \frac{18}{5} kmph$
=> 15 imps = 3 × 18 kmph = 54 kmph

•°• Speed of train (in kmph) = 15 kmph

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Hope it helps