Question

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Answer 1

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Answer 2

$\bf{\underline{Question:-}}$

• by what number should we divide 5×6/7 to get 1×2/3

$\bf{\underline{Given:-}}$

• First rational number = 5×6/7 = 41/7

$\bf{\underline{Solution:-}}$

Let,

• The number be x

$\sf → 5 × \frac{6}{7} × x = 1×\frac{2}{3}$

$\sf → \frac{41}{7x} = \frac{5}{3}$

$\sf → \frac{41}{7x} = \frac{5}{3}$

$\sf → 21x = 205$

$\sf → x = \frac{205}{21}$

$\sf → x = 9×\frac{16}{21}$

$\bf{\underline{Hence:-}}$

• The required number is 9 × 16/21