Question

please it's very urgent​

Answer 1

Answer:

$\frac{d}{dx} ( {sin}^{ - 1} (sin( \frac{\pi}{2} - 3x)) \\ \\ = \frac{d}{dx} ( \frac{\pi}{2} - 3x) \\ = 0 - 3 \\ = - 3$

Answer 2

Answer:

-3

Step-by-step explanation:

y=sin-1(cos 3x)dy/dx=2

y=sin-1(cos 3x)

y=sin-1[sin(π/2-3x)]. sin theata=cos(π/2-theta

y=π/2-3x. ) cos theta=sin(π/2-thea

dy/dx=0-3*1. ta)

dy/dx=-3