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principal=₹6500
time=4 yrs let it be n
amount after 4 yrs =₹8840
let the rate of interest be r%p.a
to find:
in what time ₹ 1600 will amount to ₹1816 at same rate
A.T.Q.,
s.i=amount-principal=8840-6500
=₹2340
si=(p×r×t)/100
2340=(6500×r×4)/100
2340×100=6500×r×4
(2340×100)/(6500×4)=r
r=9%p.a
if,
p=₹1600
a=₹1816
si=₹(1816-1600)
=₹216
216=(1600×9×t)/100
(216×100)/(1600×9)=t
time =1.5 yrs
time=4 yrs let it be n
amount after 4 yrs =₹8840
let the rate of interest be r%p.a
to find:
in what time ₹ 1600 will amount to ₹1816 at same rate
A.T.Q.,
s.i=amount-principal=8840-6500
=₹2340
si=(p×r×t)/100
2340=(6500×r×4)/100
2340×100=6500×r×4
(2340×100)/(6500×4)=r
r=9%p.a
if,
p=₹1600
a=₹1816
si=₹(1816-1600)
=₹216
216=(1600×9×t)/100
(216×100)/(1600×9)=t
time =1.5 yrs
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