Question

PLEASE ITS IMPORTANT​

Answer 1

5(root3x+root2x-6root2-4root3)/5(root3-root2)=1

root3x+root2x-6root2-4root3=root3-root2

root3x+root2x=5(root3+root2)

X(root3+root2)=5(root3+root2)

so, x=5

Answer 2

Solution:

[(x-2√6)(5√3+5√2)]/(5√3-5√2)=1

=> [(x-2√6)×5(√3+√2)]/[5(√3-√2)]=1

=> [(x-2√6)×(√3+√2)]/[(√3-√2)]=1

=> x-2√6 = (√3-√2)/(√3+√2)

Rationalising the denominator, we get

=>(x-2√6) = (√3-√2)²/[(√3+√2)(√3-√2)]

=> x-2√6 = (√3-√2)²

=>x-2√6 = (√3)²+(√2)²-2*√3*√2

=> x-2√6 = 3+2-2√6

=> x -2√6 = 5 - 2√6

compare both sides , we get

x = 5

Therefore,

Option (4) is correct.

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