please its urgent answer is 6400m^2 wrong answer will reported
Answers
Refer The Attachment ⬆️
Required Area of the Field
- 6300m²
Area of Triangle = 1/2×Base×Height
Area of Trapezium = (a+b)/2×Height
Hope It Helps You ✌️
Step-by-step explanation:
Solution :-
Th given figure consists of 4 triangles and 1 Trapezium
Area of the figure is equal to the sum of the areas of 4 triangles and one Trapezium
I) Area of ∆ ABF :-
Base of the triangle = AF = 60 m
Height of the triangle = BF = 60 m
Area of the triangle = (1/2) base × height
=> (1/2)×AF×BF
=> (1/2)×60×60 sq.m
=> 60×30
=> 1800 sq.m
Area of ∆ABF = 1800 sq.m
II) Area of Trapezium BFHC :-
Parallel sides of the Trapezium are
BF = 60 m
CH = 50 m
Distance between two parallel sides = FH
=> FG+GH
=> 10 + 10 m
=> 20 m
We know that
Area of a Trapezium = (1/2)h(a+b)
=> (1/2)×FH (BF+CH)
We have , h = 20 m , a = 60 m , b = 50 m
=> (1/2)×20(60+50)
=>10×110
=>1100 sq.m
Area of Trapezium BFHC = 1100 sq.m
III)Area of ∆ CDH :-
Base of the triangle = DH = 50 m
Height of the triangle =CH = 40 m
Area of the triangle = (1/2) base × height
=> (1/2)×DH×CH
=> (1/2)×50×40 sq.m
=> 50×20
=> 1000 sq.m
Area of ∆CDH = 1000 sq.m
IV)Area of ∆ AGE :-
Base of the triangle = GE = 40 m
Height of the triangle = AG
=> AF+FG
=> 60 m +10 m = 70 m
Area of the triangle = (1/2) base × height
=> (1/2)×AG×GE
=> (1/2)×40×70 sq.m
=> 20×70
=> 1400 sq.m
Area of ∆AGE = 1400 sq.m
V)Area of ∆ DEG :-
Base of the triangle = DG
=>DH+HG
=> 40 m + 10 m
=> 50 m
Height of the triangle = GE = 40 m
Area of the triangle = (1/2) base × height
=> (1/2)×DG×GE
=> (1/2)×50×40 sq.m
=> 50×20
=> 1000 sq.m
Area of ∆DEG = 1000 sq.m
Area of the given figure =
Area of ∆ABF+Area of Trapezium BFHC+Area of ∆CDH+Area of ∆AGE+Area of ∆DEG
1800+1100+1000+1400+1000
= 6300 sq.m
Answer:-
Area of the given figure is 6300 m²
Used formulae:-
1.Area of the triangle = (1/2) base × height
2.Area of a Trapezium = (1/2)h(a+b)
Where, a and b are parallel sides of Trapezium
h is the distance between them