Question

Please its urgent do fast ​

Answer 1

Answer:

this is the answer.

Step-by-step explanation:

note that x = 2 is a zero of the polynomial:  

2(2)³ - 3(2)² - 17(2) + 30 =  

2(8) - 3(4) - 34 + 30 =  

16 - 12 - 4 = 0  

then the polynomial is divisible by (x - 2):  

let's verify this by synthetic division:  

...2 | 2...- 3.....-17....+30  

......|  

......| .....+4.....+2.....-30  

-----------------------------------  

.......2....+1.....-15.......0  

we get:  

(2x³ - 3x² - 17x + 30) /(x - 2) = 2x² + (1)x - 15  

therefore:  

(2x³ - 3x² - 17x + 30) = (x - 2)(2x² + x - 15)  

let's now factor the quadratic replacing x with 6x - 5x:  

2x² + x - 15 = 2x² + 6x - 5x - 15 =  

(factoring by grouping)  

2x(x + 3) - 5(x + 3) =  

(factoring the common term (x + 3))  

(x + 3)(2x - 5)  

thus the answer is:  

(2x³ - 3x² - 17x + 30) = (x - 2)(x + 3)(2x - 5)  

Hope it helps you......