Question

please jaldi batao koi detail ma​

Answer 1

Answer:

multiply it with √3+√2-√5/√3+√2-√5

Step-by-step explanation:

then the denominator will be 3-2+5 which is -4

numerator will be 3√3+3√2-3√5 I think...

hope it helps

Answer 2

$\huge \fbox \green{❤Solution:}$

We Have

$\frac{3}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} } = \frac{3}{( \sqrt{3 } - \sqrt{2}) + \sqrt{5} } \times \frac{( \sqrt{3 } - \sqrt{2}) - \sqrt{5} }{( \sqrt{3} - \sqrt{2}) - \sqrt{5} }$

$= \frac{3( \sqrt{3} - \sqrt{2} - \sqrt{5}) }{( \sqrt{3} - \sqrt{2} {)}^{2} - ( \sqrt{5} {)}^{2} } =$

$\frac{3( \sqrt{3} - \sqrt{2} - \sqrt{5}) }{[( \sqrt{3} {)}^{2} + ( \sqrt{2} {)}^{2} - 2 \times \sqrt{3} \times \sqrt{2} ] - 5}$

$= \frac{3( \sqrt{3} - \sqrt{2} - \sqrt{5} }{(3 + 2 - 2 \sqrt{6} ) - 5} = \frac{3( \sqrt{3} - \sqrt{2} - \sqrt{5} ) }{ - 2 \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} }$

$= \frac{( \sqrt{18} - \sqrt{12} - \sqrt{30}) }{ - 2 \times 6} =$

$\frac{3(3 \sqrt{2} - 2 \sqrt{3} - \sqrt{30} }{ - 12}$

$= \frac{3 \sqrt{2} - 2 \sqrt{3} - \sqrt{30} }{ - 4} = \frac{2 \sqrt{3} + \sqrt{30} - 3 \sqrt{2} }{4}$

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$