Question

please jaldi batao koi detail ma bro/sis​

Answer 1

let angle B be x,

180 = 106+x

x=180-106=76

let angle c be y

y=180-118=62

x+y+angle a =180

76+62+angle a =180

angle a = 180-138=42

angle a = 42

angle b = 76

angle c = 62

Hope it helps!

Answer 2

Answer:

Angle DBA(106°) + Angle ABC= 180°

Angle ABC = 180°- Angle DBA(106°)

Angle ABC = 74°

Now

Angle ACE(118°)+ Angle ACB= 180°

Angle ACB = 180°- Angle ACE(118°)

Angle ACB = 62°

Angle ACB + Angle ABC +Angle BAC = 180°

Angle BAC = 180°- (Angle ACB + Angle ABC)

Angle BAC = 180° -(62°+74°)

Angle BAC =180°-(136°)

Angle BAC = 44°