Question

please jaldi full solve krna hai​

Answer 1

Answer:

CARNOT ENGINE

OPTION A

Explanation:

♣ THERMODYNAMICS ♥

★ GIVEN ;

★ » Temperature of Source ( T¹ ) = 427°C ≈ 700 Kelvin

★» Temperature of Sink ( T² ) = 77° C

≈ 350 Kelvin

★★ EFFICIENCY OF CARNOT ENGINE ( ẞ ) = ??

_________ [ BY USING FORMULA ] __________

$\beta \: =( 1 \: - \frac{ {t}^{2} }{ {t}^{1} } )$

★ ẞ = [ 1 - 350 / 700 ]

» ẞ = [ 700 - 350 / 700 ]

» ẞ = [ 350 / 700 ] = ( 1 / 2 )

★ →[ %ẞ = 1 / 2 × 100 = 50 % ] ← ★

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ANSWER :- HENCE ,EFFICIENCY OF HEAT ENGINE IS ;

♣ ẞ = 50 % ♣