Question

please jaldi kar do I need urgent​

Answer 1

Hope it will help you.....

Answer 2

Answer:

x=2 , y= -8/3

Step-by-step explanation:

$\sqrt[3]{ {a}^{6} { b}^{ - 4} } = {a}^{x} {b}^{2y} \\ {a}^{ \frac{1}{3} \times 6 } \times {b}^{ \frac{1}{3} \times - 4 } = {a}^{x} {b}^{2y} \\ {a}^{2} {b}^{ \frac{ - 4}{3} } = {a}^{x} {b}^{2y} \\ x = 2 \\ y = \frac{ - 8}{3}$