Math, asked by preraknagpal, 1 year ago

please jaldi reply karo

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Answered by usra88
1
angle DAB+angleABC = 180°
85°+angle DBA+angle/DBC=180°
85+angle DBA+55=180°
angleDBA= 180°-85°-55°
angleDBA=40°

usra88: angle ADB=angle CDB=40°
usra88: angle ADB=angle CDB=40°
usra88: angle DBA =angle CDB= 40°
usra88: sorry network problem so comment is repeated
Answered by SmãrtyMohït
3
❤❤Here is your answer ✌ ✌

\huge {\red {\bold {Answer}}}
according to rule of parallelogram

angle A=Angle C

85°=Angle C

angle CBD=55°[given]

now In triangle CBD

Angle C+angle CBD+angle CDB=180°(triangle sum)

85°+55°+angle CDB=180°

angle CDB+140=180°

angle CDB=180°-140°

angle CDB=40°
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