please jaldi reply karo
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1
angle DAB+angleABC = 180°
85°+angle DBA+angle/DBC=180°
85+angle DBA+55=180°
angleDBA= 180°-85°-55°
angleDBA=40°
85°+angle DBA+angle/DBC=180°
85+angle DBA+55=180°
angleDBA= 180°-85°-55°
angleDBA=40°
usra88:
angle ADB=angle CDB=40°
Answered by
3
❤❤Here is your answer ✌ ✌
according to rule of parallelogram
angle A=Angle C
85°=Angle C
angle CBD=55°[given]
now In triangle CBD
Angle C+angle CBD+angle CDB=180°(triangle sum)
85°+55°+angle CDB=180°
angle CDB+140=180°
angle CDB=180°-140°
angle CDB=40°
according to rule of parallelogram
angle A=Angle C
85°=Angle C
angle CBD=55°[given]
now In triangle CBD
Angle C+angle CBD+angle CDB=180°(triangle sum)
85°+55°+angle CDB=180°
angle CDB+140=180°
angle CDB=180°-140°
angle CDB=40°
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