Question

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Answer 1

Answer:

The given AP is 3, 5, 7, 9, 11, … Its first term = 3 and common difference = (5-3) = 2. ∴ a= 3 and d = (5-3) = 2. =3+(n-1)×2=(2n+1) [∵a=3andd=2].

Answer 2

Given:

• 3 , 5 , 7 ,9 ,11.... are in AP

To find :

• i) nth term ii) 16th term

Solution :

i) nth term

As we know that :

=> nth term = a + (n - 1)d

• a= 3 and d = 5-3 = 2

=> nth term = 3 + (n-1) 2

=> nth term = 2n +1

ii) 16th term

=> 3 + ( 16-1)2

=> 3 + 15×2

=> 3 + 30

=> 33.