Question

Please just draw the diagram n show..no need it solve
From a point, 36m above the surface of a lake, the angle of elevation
of a bird is observed to be 30° and angle of depression of its image
in the water of the lake is observed to be 60°. Find the actual height
of the bird above the surface of the lake.
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Answer 1

Pls refer the above image. I have just Drawn it roughly. You can give the namings as per your convenience.

Hope this helps

Answer 2

The actual height of the bird

above the surface of the lake is 48m.

• Let P be the point 36 m above the surface.

• L be the point on the lake(image of bird) at which angle of declination is 60°

• B be the point at which bird is present and angle of inclination is 30°

• Let M be a point on the line joining B and L such that PM is parallel to ground.

• So ML is also 36 m.

•Now, tan 60°= ML/PM

•√3 = 36/PM

• PM = 36/√3

• PM = 12√3

•Now, tan 30° = BM/PM

• 1/√3 = BM /(12√3)

• BM =12

•So total height = BM + ML

= 12 + 36

=48 m

Hope it helps you mark as brainliest please