Question

please keep me sums​

Answer 1

Given :-

• Two parallel lines intersect at ΔA

• Angle A = 50°

Solution :-

Here,

We know the value of angle A = 50°

In the given figure,

Angle C is vertically opposite angle of Angle A.

As we know that,

Vertically opposite angles are equal.

Therefore,

Angle A = Angle C = 50°

Now,

Angle C and Angle B are linear pair.

[ Linear pair is the pair of adjacent angles which formed by the intersection of two lines ]

As we know that,

Sum of linear pair = 180°

Therefore,

Angle B + Angle C = 180°

Angle B + 50° = 180°

Angle B = 180° - 50°

Angle B = 130°

Here,

Angle D is vertically opposite angle of Angle B

Therefore,

Angle B = Angle D = 130°

Hence, The four angles are. Angle A = 50° , Angle B = 130° , Angle C = 50° , Angle D = 130° $.$

Answer 2

Given :

• Line l and m intersect at a point
• $\angle \: a \: = 50 °$

To find :

measures of angle b,c,d

Solution :

measure of $\sf \angle \: a = 50 \degree$

In given figure,

$\sf \angle \: c$ is vertically opposite angle of $\sf \angle \: a$

$\sf \therefore \:\boxed{ \sf\angle \: a = \angle \: c = 50 \degree}$

$\sf \angle \: b$ and $\sf \angle \: a$ are linear pair.

$\boxed{ \sf \: sum \: of \: linear \: pair = 180 \degree}$

$\sf \implies \angle \: a + \angle \: b = \: 180 \degree$

$\sf \implies50 + \angle \: b = 180 \\ \\ \boxed{ \sf\angle \: b = 130 \degree}$

$\sf \angle d$ is vertically opposite angle of $\sf \angle \: b$

$\sf \: \therefore \angle \: b = \angle \: d \\ \\ \boxed{ \sf \angle \: d = 130 \degree}$