please kindly answer
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ʜᴇʏ ᴍᴀᴛᴇ!!
ʜᴇʀᴇ's ᴜʀ ᴀɴsᴡᴇʀ ᴅᴇᴀʀ:-)
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x-1/x=3
(x-1/x)^3= x^3-1/x^3-3× x ×1/x(x-1/x)
ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ x-1/x=3
(3)^3=x^3-1/x^3-3(3)
27=x^3-1/x^3-9
x^3-1/x^3=27+9
x^3-1/x^3=36 ᴀɴs...
___________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs☺️☺️
ʜᴇʀᴇ's ᴜʀ ᴀɴsᴡᴇʀ ᴅᴇᴀʀ:-)
___________________________________________
x-1/x=3
(x-1/x)^3= x^3-1/x^3-3× x ×1/x(x-1/x)
ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ x-1/x=3
(3)^3=x^3-1/x^3-3(3)
27=x^3-1/x^3-9
x^3-1/x^3=27+9
x^3-1/x^3=36 ᴀɴs...
___________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs☺️☺️
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0
First cube both sides. Then use the identity (x+1/x)^3=x^3+1/x3 +3×x2×1/x+3x×1/x2= x3+1/x3+3x+3/x
This is equal to 3^3=27
X3+1/x3=27+3x+3/x=27+3(x+1/x)
Solve rhs you will get the answer
Try
This is equal to 3^3=27
X3+1/x3=27+3x+3/x=27+3(x+1/x)
Solve rhs you will get the answer
Try
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