Question

Please kindly answer my 16th question with step by step explanation....
Please.....

Answer 1

Answer:

Let the ratio of angle P , Q , R be 3x : 2x : x

We know that the sjm of int. angles of a ∆ is 180°

So,

P + Q + R = 180°

3x + 2x + x = 180°

6x = 180°

x = 180°/6

x = 30°

angleR = x = 30°

anglePRT = 90° ( given)

Now,

We know that the sum of angles on straight line is 180°

angleR + anglePRT + angleTRS = 180°

30° + 90° + angleTRS = 180°

angleTRS + 120° = 180°

angleTRS = 180°- 120°

angleTRS = 60° Ans...

Answer 2

Answer:

<TRS = 60°

Step-by-step explanation:

In Δ PQR, ∠ P : ∠ Q : ∠ R = 3 : 2 : 1.

RT ⊥ PR, then ∠ PRT = 90°.

Ratio of the angles of the Δ PQR = ∠ P : ∠ Q : ∠ R = 3 : 2 : 1

=> ∠R = (1/6) * 180

          = 30°

Now,

=> ∠PRQ + ∠PRT + ∠TRS = 180°

=> 30° + 90° + <TRS = 180°

=> ∠TRS = 60°

Therefore, the value of ∠TRS = 60°.

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