Chemistry, asked by emaanfatima83, 8 days ago

please kindly explain me briefly that's what is poh of 0.02M Ca(OH)2.

Answers

Answered by bff12345arushakshata

1

Answer:

pOH = -log 10 [HO-]

[HO-] = 0.04×mol×L^(-1)

pOH = - log 10 (0.04) = -(-1.40) = 1.40

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