Question

please kindly solve the below equation in details and in simple way

Q.1 the sum of three consecutive multiples of 8 is 888. find the multiples

Answer 1

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Solution:--


suppose three multiples are x-1,x,x+1 th multiples of 8.

Their sum is 888. So, 8(x-1)+8x+8(x+1)=888

24x=888

3x=111.

x=111/3=37.
Multiples are:

8(x-1)=8*36=288
8*37=296

8*38=304.

Answer 2

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Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 888

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

Take 24 on the RHS

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304

If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

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