Question

please koi copy me ye question kar k de do yar bhout der se try kr rha hu wrong answer aara h har bar​

Answer 1

Step-by-step explanation:

Given that,

$\displaystyle\longrightarrow{\Bigg[\dfrac{ \big({11} \big)^{ \frac{2}{4} } }{ { \big(11 \big)}^{ \frac{3}{2} } }\Bigg] }^{ \frac{1}{4} + \frac{2}{3} }$

By applying following exponential law . . .

$\rm\implies \dfrac{A^{x} }{ {A}^{y} } = { \big(A \big) }^{x - y}$

. . . We get,

$\displaystyle\longrightarrow{\Bigg[{ \big({11} \big)^{ \frac{2}{4} - \frac{3}{2} } }\Bigg] }^{ \frac{1}{4} + \frac{2}{3} }$

Now simplifying this,

$\displaystyle\longrightarrow{\Bigg[{ \big({11} \big)^{ \frac{2 - 6}{4} } }\Bigg] }^{ \frac{8 + 3}{12}}$

$\displaystyle\longrightarrow{\Bigg[{ \big({11} \big)^{ \frac{ - 4}{4} } }\Bigg] }^{ \frac{11}{12}}$

$\displaystyle\longrightarrow{\Bigg[{ \big({11} \big)^{ - 1 } }\Bigg] }^{ \frac{11}{12}}$

Final answer is,

$\displaystyle\longrightarrow{\Big[{ {11}}\Big] }^{ - \frac{11}{12}}$