Question

please koi to iska Answer de do Please Hath jod raha hu​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

(a) (-4)^4 ÷ (-4)^8

$= > using \: a^{m} \div {a}^{n } = {a}^{m - n}$

$= > ( - 4) ^{4 - 8}$

$= > ( - 4)^{ - 4}$

$= > \frac{1}{( - 4)^{4} }$

$= > \frac{ 1}{256}$

(b) (3^-7 ÷ 3^-10) × 3^-5

$= > ({3}^{ - 7 - ( - 10)} ) \times {3}^{ - 5}$

$= > {3}^{ - 7 + 10} \times {3}^{ - 5}$

$= > {3}^{3} \times {3}^{ - 5}$

$= > {3}^{3 + ( - 5)}$

$= > {3}^{3 - 5}$

$= > {3}^{ - 2}$

$= > \frac{1}{{3}^{2} }$

$= > \frac{1}{9}$

(c) (5^m ÷ 5^-3) = 5^5

$= > {5}^{m - ( - 3)} = {5}^{5}$

$= > {5}^{m + 3} = {5}^{5}$

Cancelling base 5 from both the sides,

$= > m + 3 = 5$

$= > m = 5 - 3$

$= > m = 2$