Question

please let me know how to do it

Also do it fast friend please
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Answer 1

Answer:

There are two possible values for x:

x = 0  ( makes both sides equal to -2 )

OR

x = ( 2ab - ac - bc ) / ( a + b - 2c )

I hope this helps!

Step-by-step explanation:

Given equation

=> a(x-b)(x-c) + b(x-a)(x-c) = 2c(x-a)(x-b)

=> (a + b - 2c) x²  -  ( ac + ab + ab + bc - 2ac - 2bc ) x + ( abc+abc-2abc ) = 0

=> (a + b - 2c) x²  -  ( 2ab - ac - bc ) x = 0

=> either  x = 0

    or   (a + b - 2c) x - (2ab - ac - bc) = 0  =>  x = (2ab - ac - bc) / (a + b - 2c)