Question

Please let me know if you know how to do the same

Answer 1

see the image attach here

Answer 2

Hello mate!❤❤

Here is your answer!

Given that, $a^{2} + \frac{1}{a^{2} } = 23$

We have to find the value of $a + \frac{1}{a}$

Now we use the formula (a+b)² = a² + 2ab + b²

$(a + \frac{1}{a} )^2 = a^2 + 2ab + b^2$

$(a + \frac{1}{a})^2 = a^2 + 2(a)(\frac{1}{a}) +( \frac{1}{a})^2$

$(a + \frac{1}{a} )^2 = a^2 + 2 + \frac{1}{a^2}$

$(a + \frac{1}{a} )^2 = a^2 + \frac{1}{a^2} + 2$

Now we substitute the value of a² + 1/a²,

$(a + \frac{1}{a} )^2 = 23 + 2$

$(a + \frac{1}{a} )^2 = 25$

Now, we bring the root to the other side,

$(a + \frac{1}{a} ) = \sqrt{25}$

$(a + \frac{1}{a} ) = 5$

∴ $(a + \frac{1}{a} ) = 5$

Hope it helps!

#BeBrainly