Question

please let me know the answer​

Answer 1

${4}^{x} = 64 \\ { ({2}^{2} )}^{x} = {8}^{2} \\ {2}^{2x} = {( {2}^{3} )}^{2} \\ {2}^{2x} = {2}^{6} \\ ∴2x = 6 \\ ∴x = 3$

Now,

${12}^{2x - 6} \\ = {12}^{2(3) - 6} \\ = {12}^{6 - 6} \\ = {12}^{0} = 1$