Question

please let me know the answer fast​

Answer 1

Answer:

this is the answer...

please mark brainliest.........

Answer 2

Question-

The Unit of Electrostatic Constant 'k' in Coulomb's law is

SoLution-

Coulomb Electric force is given by

$\sf{\pink{F= k \dfrac{q_1q_2}{r^2}}}$

$\sf{k= \dfrac{F r^2} {q_1 q_2 } }$

where,

F = Electric force

k = Coulomb constant

$q_1, q_2$= Charges

r = Distance of separation. of charges from their centre

we know the unit of

F= Newton [N] or [Kgm/s²]

q= Coulomb [C] or [A/s]

r= meter [m]

Now,

$\sf{\green{k= \dfrac{F r^2} {q_1 q_2 } }}$

$\sf{ \green{\implies k= \dfrac{Nm^2 }{C^2 } }}$

$\sf{\green{\implies k= \dfrac{kg \times \dfrac{m}{s^2 } \times m^2 } {A^2\times s^2 }}}$

$\sf{\implies \boxed{\green{\bf{k= \dfrac{kgm^3}{A^2 s^4 } }}}}$

Option 2nd is correct