Question

? Please let me know the answer i will mark u the brainliest

Answer 1

Ahoy,

Let the 1st digit(digit at tens place) be x
then the other digit(digit at ones place) be 7-x

(because we are given that x+other digit = 7
so, other digit = 7-x)

The number is 10x+7-x
=9x+7

Now ,
When the digits are reversed then, the digit at ones place will be in tens place and vice- versa.

So,
Now, the number is = 10(7-x)+x
=> 70-10x+x
=>70-9x

According to Question:-
70-9x= (9x+7)-9
=> 70-9x= 9x +7-9
=>70-9x = 9x -2
=>70+2 =9x+9x
=>72=18x
=>x= 72/18
=>x = 4

The other digit is 7-x =7-4 = 3

There fore the number is
43


Cheers!