Question

please let me know the answer of this question​

Answer 1

Answer:

I got only half answer another portion I didn't got that

Answer 2

Answer:

d) $(\frac{49}{29} ,\frac{19}{29} )$

Step-by-step explanation:

3x + 6y = 9

3x = 9 - 6y

$x = \frac{9 - 6y}{3}$ –––(1)

Putting (1) into the 2nd equation,

7x - 15y = 2

$7( \frac{9 - 6y}{3}) - 15y = 2$

$\frac{63 - 42y}{3} - 15y = 2$

$\frac{63 - 42y - 45y}{3} = 2$

63 - 42y - 45y = 2 × 3

63 - 87y = 6

- 87y = 6 - 63

- 87y = 57

$y = \frac{57}{87} = \frac{19}{29}$ –––(2)

Putting (2) into (1),

$x = \frac{9 - 6y}{3}$

$x = \frac{9 - 6( \frac{19}{29}) }{3}$

$x = \frac{9 - \frac{114}{29} }{3}$

$x = \frac{ \frac{261 - 114}{29} }{3}$

$x = \frac{ \frac{147}{29} }{3}$

$x = \frac{147}{29 \times 3}$

$x = \frac{147}{87} = \frac{49}{29}$

The point of intersection of lines is $(\frac{49}{29} ,\frac{19}{29} )$