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∠A - ∠B=15°. (GIVEN). .........(eq1)
∠B- ∠C=30°. (GIVEN). ...........(eq2)
from eq 1
∠A= 15°+∠B
from eq2
∠C = ∠B-30°
∠A+∠B+∠C=180°. (ASP)
(15°+∠B)+∠B+(∠B-30°) =180° (from eq 1 & 2)
3∠B - 15°=180°
3∠B =180° +15°
3∠B = 195°
∠B = 195/3 = 65°
∠A = 15°+∠B = 15° + 65°=80°
∠C = ∠B-30° = 65° - 30°=35°
∠A=80°
∠B= 65°
∠C=35°
∠B- ∠C=30°. (GIVEN). ...........(eq2)
from eq 1
∠A= 15°+∠B
from eq2
∠C = ∠B-30°
∠A+∠B+∠C=180°. (ASP)
(15°+∠B)+∠B+(∠B-30°) =180° (from eq 1 & 2)
3∠B - 15°=180°
3∠B =180° +15°
3∠B = 195°
∠B = 195/3 = 65°
∠A = 15°+∠B = 15° + 65°=80°
∠C = ∠B-30° = 65° - 30°=35°
∠A=80°
∠B= 65°
∠C=35°
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