Question

please let me know this answer yrrrrrrrrr

Answer 1

PS = 3 cm
 and, SR = 4 cm

So, PR = 4 + 3 = 7 cm

Now, ST║RQ
so, triangles PST and PRQ are similar [∵Alternate angles are equal]

Hence, ar(PST)/ar(PRQ) = PS²/PR² = 3²/7² = 9/49 = 9:49

Answer 2

Given:

PS = 3 cm

SR = 4 cm

PR = PS + SR = 4 + 3 = 7 cm

ST║QR



To Find:

Ratio of area of ΔPST and ΔPRQ



Solution:

To find the ratio of PS and PR

 = PS/SR  ⇒ 3/7

( Note:- We don't want to use BPT here as it is not required )

as ST║QR It gives us that  "ΔPST similar to ΔPQR" 


Area of ΔPST/Area of ΔPQR = PS²/SR²

(By Theorem - Ratio of Area of similar triangles equals to their square of corresponding sides)

Area of ΔPST/Area of ΔPQR = 3²/7²

                                               = 9/49


Hence their ratio of areas = 9:49

☺ Hope this Helps ☺