Please make correctly qno2 only
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1/2 (sum of parallel sides)× distance = area of trapezium
1/2 (20 + side b)×15 = 480
1/2 (20 + side b)×15 = 480
amit800:
hey the answer is 44m
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Area of ttrapezium = 1/2(a+b)× h.
Let us take the second parallel side be x.
Then its area = 1/ 2( a+ b) × h
=1/2(20+ x)×15m^2
But it is given 480m^2.
So ATQ , 1/2(20 +x)×15= 480m^2
or. 20+x. = 480 × 2/15 m.
or. 20+x = 64m.
or x=( 64 -20) m.
Therefore x = 54m.
Therefore the measure of the second side is 44m.
Hope it helps you .
Let us take the second parallel side be x.
Then its area = 1/ 2( a+ b) × h
=1/2(20+ x)×15m^2
But it is given 480m^2.
So ATQ , 1/2(20 +x)×15= 480m^2
or. 20+x. = 480 × 2/15 m.
or. 20+x = 64m.
or x=( 64 -20) m.
Therefore x = 54m.
Therefore the measure of the second side is 44m.
Hope it helps you .
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